1155B - Game with Telephone Numbers - CodeForces Solution

games greedy implementation *1200

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Python Code: 

n=int(input())
a=list(map(int,input()))
m=int((n-11)/2)
b=a[0:2*m+1]
if b.count(8)>m :
    print("YES")
else:
    print("NO")

C++ Code: 

#include <bits/stdc++.h>
using namespace std;

int n, i, h;
vector <int> vec_8;
vector <int> vec_n8;
char c;

int main()
{

    cin >> n;

    for (i = 1; i <= n; i++)
    {
        cin >> c;

        if (c == '8') vec_8.push_back(i);
        else vec_n8.push_back(i);
    }

    h = (n - 11)/2;

    if (h >= vec_8.size()) cout << "NO" << endl;
    else if (h >= vec_n8.size()) cout << "YES" << endl;
    else
    {
        if (vec_8[h] < vec_n8[h]) cout << "YES" << endl;
        else cout << "NO" << endl;
    }

}


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